Ja Perm

A 1×2×3 block is already solved: a full bar of three plus a two-sticker bar on the next side. Ja and Jb are mirror images.

R' U L' U2 R U' R' U2 R L

10 moves · Probability 1/18 · Corners UBL↔UBR · Edges UL↔UB · Mirror: Jb Perm

Ja Perm

Setup: apply these moves to a solved cube to reach this caseL' R' U2 R U R' U2 L U' R

Other algorithms

Dashed keys are AUF: a U turn that lines the top layer up with this algorithm.

  1. U' L' U' L F L' U' L U L F' L2 U L U'